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Q2 of 227 Page 89

Find the GCD of the following

x2 + 14x + 33, x3 + 10x2 – 11x

Given,


X2 + 14x + 33 = x2 + 3x + 11x + 33 = x(x + 3) + 11(x + 3)


= (x + 11)(x + 3)


X3 + 10x2 – 11x = x(x2 + 10x – 11) = x(x2 + 11x – x – 11)


= x[x(x + 11) – 1(x + 11)]


= x(x + 11)(x – 1)


Greatest common divisor = (x + 11)


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Questions · 227
3. Algebra
1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 1 1 1 1 1 1 2 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 2 2 3 3 3 3 1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 2 3 4 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 1 2 3 4 5 6 7 8 9 10 1 1 1 1 1 1 2 2 2 2 3 4 5 6 7 1 1 1 1 2 3 4 5 6 7 8 9 10 11 12 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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