Q1 of 227 Page 79

Solve the following systems of equation using cross multiplication method.

The given equations are


– = – 2 … (1)


+ = 13 … (2)


Let a = and b =.


⇒ 5a – 4b + 2 = 0 … (3)


⇒ 2a + 3b – 13 = 0 … (4)


For cross multiplication method, we write the coefficients as



Hence, we get = =


⇒ = =


⇒ = =


⇒ a = = 2


⇒ b = = 3


When a = 2, = 2. Thus, x = 1/2.


When b = 3, = 3. Thus, y =.


∴ (,) is the solution to the given system.


More from this chapter

All 227 →
1

Solve the following systems of equation using cross multiplication method.

0.5x + 0.8y = 0.44, 0.8x + 0.6y = 0.5

 1

Solve the following systems of equation using cross multiplication method.

 2

Formulate the following problems as a pair of equations, and hence find their solutions:

One number is greater than thrice the other number by 2. If 4 times the smaller number exceeds the greater by 5, find the numbers.

 2

Formulate the following problems as a pair of equations, and hence find their solutions:

The ratio of income of two persons is 9: 7 and the ratio of their expenditure is 4: 3. If each of them manages to save ₹ 2000 per month, find their monthly income.