Q1 of 227 Page 79

Solve the following systems of equation using cross multiplication method.

The given equations are


– = – 2 … (1)


+ = … (2)


By taking LCM,


(1) becomes 9x – 10y + 12 = 0


(2) becomes 2x + 3y – 13 = 0


For cross multiplication method, we write the coefficients as



Hence, we get = =


⇒ = =


⇒ = =


⇒ x = = 2


⇒ y = = 3


∴ (2, 3) is the solution to the given system.


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