Find the values of k for which the roots are real and equal in each of the following equations
x2 + 2k (x – 2) + 5 = 0
x2 + 2k (x – 2) + 5 = 0
⇒ x2 + 2kx – 4k + 5 = 0
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⇒ 4k2 + 16k – 20 =0
Divide by 4
⇒ k2 + 4k – 5 = 0
⇒ k2 + 5k – k – 5 = 0
⇒ k(k + 5) – (k + 5) =0
⇒ (k + 5)(k – 1) = 0
k + 5 = 0 or k – 1 = 0
k = –5 or k = 1
∴ k = –5 and k = 1
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