Q2 of 227 Page 79

Formulate the following problems as a pair of equations, and hence find their solutions:

Three chairs and two tables cost ₹ 700 and five chairs and three tables cost ₹1100. What is the total cost of 2 chairs and 3 tables?

Let chairs be x and tables be y.


Then the equations are


3x + 2y = 700 i.e. 3x + 2y – 700 = 0


5x + 3y = 1100 i.e. 5x + 3y – 1100 = 0


For cross multiplication method, we write the coefficients as



Hence, we get = =


⇒ = =


⇒ = =


⇒ x = = 100 (Cost of one chair)


⇒ y = = 200 (Cost of one table)


Now, total cost of two chairs and three tables,


2x + 3y = 2 (100) + 3 (200) = 200 + 600 = Rs. 800


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