Formulate the following problems as a pair of equations, and hence find their solutions:
A train travelled a certain distance at a uniform speed. If the train had been 6 km/hr faster, it would have taken 4 hours less than the scheduled time. If the train were slower by 6 km/hr, then it would have taken 6 hours more than the scheduled time. Find the distance covered by the train.
Let the speed be x km/hr and distance travelled be y km.
We know that distance = speed × time
Scheduled time to cover distance = y/x hr
Then the first condition is
⇒
=
– 4
⇒
= ![]()
⇒ xy = (x + 6) (y – 4x)
⇒ xy = xy – 4x2 + 6y – 24x
⇒ 4x2 – 6y + 24x = 0
⇒ 2x2 – 3y + 12x = 0 i.e. 12x – 3y + 2x2 = 0
Second condition is
⇒
=
+ 6
⇒
= ![]()
⇒ xy = (x – 6) (y + 6x)
⇒ xy = xy + 6x2 – 6y – 36x
⇒ 6x2 – 6y – 36x = 0
⇒ x2 – y – 6x = 0 i.e. – 6x – y + x2 = 0
For cross multiplication method, we write the coefficients as

Hence, we get
=
= ![]()
⇒
=
= ![]()
⇒
=
= ![]()
⇒
= ![]()
⇒ – 30x = – x2
⇒ 30km/hr = x
Now,
= ![]()
⇒
= ![]()
⇒ y = 24 × 30 = 720 km
∴ The distance covered by train = 720 km
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