Q2 of 227 Page 79

Formulate the following problems as a pair of equations, and hence find their solutions:

A train travelled a certain distance at a uniform speed. If the train had been 6 km/hr faster, it would have taken 4 hours less than the scheduled time. If the train were slower by 6 km/hr, then it would have taken 6 hours more than the scheduled time. Find the distance covered by the train.

Let the speed be x km/hr and distance travelled be y km.


We know that distance = speed × time


Scheduled time to cover distance = y/x hr


Then the first condition is


= – 4


=


xy = (x + 6) (y – 4x)


xy = xy – 4x2 + 6y – 24x


4x2 – 6y + 24x = 0


2x2 – 3y + 12x = 0 i.e. 12x – 3y + 2x2 = 0


Second condition is


= + 6


=


xy = (x – 6) (y + 6x)


xy = xy + 6x2 – 6y – 36x


6x2 – 6y – 36x = 0


x2 – y – 6x = 0 i.e. – 6x – y + x2 = 0


For cross multiplication method, we write the coefficients as



Hence, we get = =


= =


= =


=


– 30x = – x2


30km/hr = x


Now, =


=


y = 24 × 30 = 720 km


The distance covered by train = 720 km


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