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Q1 of 227 Page 110

Determine the nature of the roots of the equation.

3x2 –2√6x + 2 = 0

3x2 – 2√6 x + 2 =



⇒ a = 3, b = –2√6 and c = 2


= (–2√6 )2– 4(3)(2)


24 – 24


= 0


∴ b2 – 4ac = 0. hence, roots are real and equal.


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Questions · 227
3. Algebra
1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 1 1 1 1 1 1 2 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 2 2 3 3 3 3 1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 2 3 4 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 1 2 3 4 5 6 7 8 9 10 1 1 1 1 1 1 2 2 2 2 3 4 5 6 7 1 1 1 1 2 3 4 5 6 7 8 9 10 11 12 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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