Determine the nature of the roots of the equation.
3x2 –2√6x + 2 = 0
3x2 – 2√6 x + 2 =
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⇒ a = 3, b = –2√6 and c = 2
= (–2√6 )2– 4(3)(2)
24 – 24
= 0
∴ b2 – 4ac = 0. hence, roots are real and equal.
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