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Q2 of 227 Page 89

Find the GCD of the following

2x2 – x – 1,4x2 + 8x + 3

Given,


2x2 – x – 1 = 2x2 – 2x + x – 1 = 2x(x – 1) + 1(x – 1)


= (2x + 1)(x – 1)


4x2 + 8x + 3 = 4x2 + 2x + 6x + 3 = 2x(x + 1) + 3(2x + 1)


= (2x + 1)(2x + 3)


Greatest common divisor = (2x + 1)


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Questions · 227
3. Algebra
1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 1 1 1 1 1 1 2 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 2 2 3 3 3 3 1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 2 3 4 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 1 2 3 4 5 6 7 8 9 10 1 1 1 1 1 1 2 2 2 2 3 4 5 6 7 1 1 1 1 2 3 4 5 6 7 8 9 10 11 12 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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