A takes 6 day less than the time taken by B to finish a piece of work. If both A and B together can finish it in 4 days, find the time that B would take to finish this work by himself.
Let x be the tune taken by A to finish the work.
So, x – 6 be the time taken by B to finish the work.
Work done by A in one day = ![]()
Work done by B in one day = ![]()
Number of days taken by both to finish the work = ![]()
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⇒ ![]()
⇒ ![]()
⇒ 4(2x – 6) = x2 – 6x
⇒ 8x – 24 = x2 – 6x
⇒ x2 – 6x – 8x + 24 = 0
⇒ x2 – 14x + 24 = 0
⇒ x2 – 12x – 2x + 24 = 0
⇒ x(x – 12) –2(x – 12) = 0
⇒ (x – 12)(x – 2) = 0
x – 12 = 0 or x – 2 = 0
x = 12 or x = 2
Here, 2 is not admissible.
So, B is taking 12 days to finish the work.
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