Find the quotient and remainder using synthetic division.
(3x3 + 4x2 – 10x + 6) ÷ ( 3x – 2)
Let p(x) = 3x3 + 4x2 – 10x + 6 be the dividend and arranging p(x) according to the descending powers of x.
Divisor, q(x) = 3x – 2
⇒ To find out Zero of the divisor –
q(x) = 0
3x – 2= 0
x = ![]()
So, zero of divisor is
.
And, p(x) = 3x3 + 4x2 – 10x + 6
Put zero for the first entry in the second row.

∵ p(x) = (Quotient)×q(x) + remainder.
So, 3x3 + 4x2 – 10x + 6 = (x –
)(3x2 + 6x – 6) + 2
= (3x – 2)
(3x2 + 6x – 6) + 2
Thus, the Quotient =
(3x2 + 6x – 6)= x2 + 2x – 2 and remainder is 2.
Hence, when p(x) is divided by (3x – 2) the quotient is x2 + 2x – 2 and remainder is 2.
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