Solve the following quadratic equations by completing the square.
=3x + 2
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= 5x + 7 = (3x + 2)(x – 1)
= 5x + 7 = 3x(x – 1) + 2 (x – 1)
= 5x + 7 = 3x2 – 3x + 2x –2
= 5x + 7 = 3x2 – x – 2
= 3x2 – x – 2 – 5x – 7 =0
= 3x2 – 6x – 9 = 0
Divide whole equation by 3
= x2 – 2x – 3 = 0
= x2 – 3x + x – 3 = 0
= x (x – 3) + (x – 3) = 0
= (x – 3) (x + 1) = 0
x – 3 = 0 or x + 1 = 0
x = 3 or x = –1
Couldn't generate an explanation.
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