Q3 of 227 Page 90

Find the LCM of the following

a2bc, b2ca, c2ab

Given terms: –


a2bc, b2ca, c2ab


Formula used: –


LCM = Least Common Multiple


Means it is the lowest term by which every element must be


divided completely;


a2bc = a × a × b × c


b2ca = a × b × b × c


c2ab = a × b × c × c


first find the common factors in all terms


Common factor = a × b × c


then multiply the remaining factors of terms in common


factor to get the LCM


= ( a × b × c) × [(a)(b)(c)]


= a2b2c2


Conclusion: –


The LCM of given terms [a2bc, b2ca, c2ab] is a2b2c2


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