Find the zeros of the following quadratic polynomials and verify the basic relationships between the zeros and the coefficients.
x2 – 15
Let f(x) = x2 – 15
Arranging equation in proper form.
Now, f(x) = x2 + 0x – 15
To find out zeros of the given polynomial.
We put f(x) = 0
⇒ x2 – 15 = 0
∴ x2 –
= 0
So, (x +
)(x –
) = 0
When, (x +
) = 0
Then, x = –
.
When. (x –
) = 0
Then, x = ![]()
⇒ Our zeros are α = –
and β =
.
⇒ sum of zeros = α + β = –
+ ![]()
⇒ sum of zeros = α + β = 0
⇒ Product of zeros = αβ = –
= – 15
Now, Comparing f(x) = x2 + 0x – 15 with standard equation ax2 + bx + c.
We get, a = 1, b = 0 and c = – 15.
We can verify,
⇒ Sum of zeros = ![]()
i.e. α + β = ![]()
∴ α + β = 0
⇒ Product of zeros = ![]()
αβ = ![]()
Hence, relationship between zeros and coefficient is verified.
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