Solve the following system of equation by elimination method.

The given equations are
+
= 17 … (1)
+
=
… (2)
Let a =
and b =
.
⇒ 15a + 2b = 17 … (3)
⇒ a + b =
… (4)
Now, (3) – (4) × 2
⇒ 15a + 2b – (2a + 2b) = 17 – ![]()
⇒ 15a + 2b – 2a – 2b = ![]()
⇒ 13a = ![]()
⇒ a = ![]()
Substituting a =
in (4),
⇒
+ b = ![]()
⇒ b =
= 7
When a =
,
=
. Thus, x = 5.
When b = 7,
= 7. Thus, y = ![]()
∴ (5,
) is the solution to the given system.
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