Q9 of 227 Page 73

Solve the following system of equation by elimination method.

The given equations are


+ = 17 … (1)


+ = … (2)


Let a = and b =.


15a + 2b = 17 … (3)


a + b = … (4)


Now, (3) – (4) × 2


15a + 2b – (2a + 2b) = 17 –


15a + 2b – 2a – 2b =


13a =


a =


Substituting a = in (4),


+ b =


b = = 7


When a =, =. Thus, x = 5.


When b = 7, = 7. Thus, y =


(5,) is the solution to the given system.


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