Write a value of 
We know that cos2x = 1 – sin2x
(a2sin2x + b2cos2x) = a2sin2x + b2(1 – sin2x)
= (a2 – b2)sin2x + b2
Let, sin2x = t
Differentiating both sides with respect to x
= sin 2x
⇒ dt = sin2x dx
Use formula
Again, put t = sin2x
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