Evaluate the following integrals:

Given ![]()
Rewriting, we get ![]()
Expressing the integral ![]()
![]()
![]()
Consider ![]()
By partial fraction decomposition,
![]()
⇒ x – 2 = A (2x – 1) + Bx
⇒ x – 2 = 2Ax – A + Bx
⇒ x – 2 = (2A + B) x – A
∴ A = 2 and 2A + B = 1
∴ B = 1 – 4 = -3
Thus, ![]()
![]()
![]()
Consider ![]()
We know that ![]()
![]()
And consider ![]()
Let u = 2x – 1 → dx = 1/2 du
![]()
We know that ![]()
![]()
Then,
![]()

Then,
![]()

We know that ![]()
![]()
![]()
AI is thinking…
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



