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Q41 of 865 Page 20

Evaluate the following integrals:

Assume 1 - tan²x = t

d(1 - tan²x) = dt

2.tanx.sec²xdx = dt

Substituting t and dt we get

⇒ ⇒

⇒

⇒

But t = 1 - tan²x

⇒ .

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