Q68 of 865 Page 20

Evaluate the following integrals:

Assume x3 + 1 = t2


d(x3 + 1) = d(t2)


3x2.dx = 2t.dt


⇒


x3 + 1 = t2


⇒


Substituting t and dt


⇒


⇒


⇒


⇒ x3 = t2 - 1


⇒


⇒


⇒


⇒


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