Evaluate the following integrals:
Assume 5 - x2 = t2
d(5 - x2 ) = d(t2)
- 2x.dx = 2t.dt
⇒x dx = - t.dx
⇒ 
Substituting t and dt
⇒ 
⇒ 
⇒ x2 = 5 - t2
⇒ 
⇒ 
⇒ 
⇒ 
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