Let 2x + 1 = λ(3x + 2) + μ
2x + 1 = 3xλ + 2λ + μ
comparing coefficients we get
3λ = 2 ; 2λ + μ = 1
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Replacing 2x + 1 by λ(3x + 2) + μ in the given equation we get
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