Evaluate 
Given, 
Let cosx=t
-sinx dx=dt
Now, t2-2t-3
= t2-3t+t-3
= t(t-3)+t-3
= (t-3) (t+1)
1
≅ A(t-1)+B(t-3)
Equating ’t’ coeff:-
0=A+B
A=-B
Equating constant:-
1=-A-3B
1=-(-B)-3B
1=-2B
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