Evaluate the following integrals:

Assume 10x + x10 =t
d(10x + x10) =dt
ax = logea
⇒ 10x9 + 10xloge10=dt
Put t and dt in given equation we get
⇒ ![]()
= ![]()
But t = 10x + x10
= ln|10x + x10| + c.
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