Evaluate the following integrals:
∫ {1 + tan x tan (x + θ)} dx
tan(A - B) = ![]()
∴ tan(x - (x + θ )) = ![]()
∴ tan(θ) = ![]()
⇒ tan(θ)(1 + tanx.tan(x + θ )) = tan(x) - tan(x + θ)
⇒ (1 + tanx.tan(x + θ )) = ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
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