Evaluate the following integrals:

Given ![]()
Expressing the integral ![]()
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Consider ![]()
Let
and split,
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Consider ![]()
Let ![]()
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We know that ![]()
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Now consider ![]()
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By partial fraction decomposition,
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⇒ 1 = A (x + 2) + B (x + 5)
⇒ 1 = Ax + 2A + Bx + 5B
⇒ 1 = (A + B) x + (2A + 5B)
⇒ A + B = 0 and 2A + 5B = 1
Solving the two equations,
⇒ 2A + 2B = 0
2A + 5B = 1
-3B = -1
∴ B = 1/3 and A = -1/3
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Consider ![]()
Let u = x + 2 → dx = du
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We know that ![]()
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Similarly ![]()
Let u = x + 5 → dx = du
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We know that ![]()
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Then,
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Then,
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Then,
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We know that ![]()

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