Evaluate the following integrals:

Assume a2 + b2sin2x = t
d(a2 + b2sin2x) = dt
2b2.sinx.cosx.dx=dt
(2sinx.cosx = sin2x)
Sin2xdx = ![]()
Put t and dt in the given equation we get
⇒ ![]()
= ![]()
But t = a2 + b2sin2x
=
.
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