Evaluate the following integrals:
Assume x + cos2x =t
d(x + cos2x) =dt
(1 + ( - 2cosx.sinx))dx = dt
2sinx.cosx=sin2x
(1 - sin2x)dx=dt
Put t and dt in given equation we get
⇒ 
= 
But t = x + cos2x
= ln| x + cos2x | + c.
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