Evaluate the following integral:
dx
X2 + 1 = A(x – 2)(x + 3) + B(x + 3) + C(x – 2)2
Put x = 2
4 + 1 = B × 5
5 = 5B
Put x = – 3
10 = C × 25
Equating coefficients of constants
1 = – 6A + 3B + 4C
Thus,
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