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Consider
,
Let
and II = 1
As ∫ I.II dx = I.∫ II dx - ∫ [ d/dx(I). ∫ II dx]
So,
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AI is thinking…
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
Evaluate![]()
Consider
,
Let
and II = 1
As ∫ I.II dx = I.∫ II dx - ∫ [ d/dx(I). ∫ II dx]
So,
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
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Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
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