Evaluate the following integrals:

Assume 1 + ex = t
ex = t - 1
d(1 + ex) = dt
ex dx = dt
dx = ![]()
Substitute t and dt we get
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
But t = 1 + ex
⇒ ![]()
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