Evaluate: 
let 1 + log x = t
Differentiating on both sides we get,
![]()
Substituting it in
we get,
=∫t2 dt
![]()
![]()
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Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
Evaluate: 
let 1 + log x = t
Differentiating on both sides we get,
![]()
Substituting it in
we get,
=∫t2 dt
![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
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