Evaluate the following integral:
dx
X2 + x – 1 = A(x + 1)(x + 2) + B(x + 2) + C(x + 1)2
Put x = – 2
1 = C
Put x = – 1
– 1 = B
Equating coefficients of constants
– 1 = 2A + 2B + C
Thus,
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