Evaluate 
Given, 
Now, 3x2+13x-10
= 3x2+15x-2x-10
= 3x(x+5)-2(x-5)
= (x-5) (3x-2)
1
≅ A (3x-2) + B(x+5)
Equating ‘x’ coeff: -
0=3A+B
B=-3A
Equating constant:-
1=-2A+5B
1=-2A+5(-3A)
1=-2A-15A
1=-17A
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