Evaluate the following integral:
⇒ 2x + 1=A(x – 3) + B(x – 2)
⇒ 2x + 1=(A + B)x – 3A – 2B
Equating similar terms, we get,
A + B=2 and 3A + 2B= – 1
So, A= – 5, B=7
⇒ I = – 5 log |x – 2| + 7 log |x – 3| + c
⇒ I = log |x – 2| – 5 + log |x – 3|7 + c
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