Q67 of 865 Page 20

Evaluate the following integrals:

We can write x2 + 2x + 1 + 1 = (x + 1)2 + 1


⇒


Assume x + 1 = tant


⇒ dx = sec2t.dx


⇒


⇒ tan2t + 1 = sec2t.


⇒


⇒


⇒ log|sint| + c


⇒


But tant = x + 1


⇒


The final answer is


⇒


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