Evaluate the integral

Ideas required to solve the problems:
* Integration by substitution: A change in the variable of integration often reduces an integral to one of the fundamental integration. If derivative of a function is present in an integration or if chances of its presence after few modification is possible then we apply integration by substitution method.
* Knowledge of integration of fundamental functions like sin, cos ,polynomial, log etc and formula for some special functions.
Let, I = ![]()
To solve such integrals involving trigonometric terms in numerator and denominators. We use the basic substitution method and to apply this simply we follow the undermentioned procedure-
If I has the form ![]()
Then substitute numerator as -
![]()
Where A, B and C are constants
We have, I = ![]()
As I matches with the form described above, So we will take the steps as described.
∴ ![]()
⇒
{![]()
⇒ ![]()
Comparing both sides we have:
C = 0
Bp + Aq = 1
Bq + Ap = 0
On solving above equations, we have:
A =
B =
and C = 0
Thus I can be expressed as:
I = ![]()
I = ![]()
∴ Let I1 =
and ![]()
⇒ I = I1 + I2 ….equation 1
I1 = ![]()
Let, u = pcos x + qsin x ⇒ du = (-psin x + qcos x)dx
So, I1 reduces to:
I1 = ![]()
∴ I1 =
…..equation 2
As, I2 = ![]()
∴ I2 =
…..equation 3
From equation 1 ,2 and 3 we have:
I = ![]()
∴ I = ![]()
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