Evaluate the following integral:
3x – 2 = A(x + 1)(x + 3) + B(x + 3) + C(x + 1)2
Put x = – 1
– 3 – 2 = A × 0 + B × ( – 1 + 3) + C × 0
– 5 = 2B
Put x = – 3
– 9 – 2 = C × ( – 2)( – 2)
– 11 = 4C
Equating coefficients of constants
– 2 = 3A + 3B + C
Thus,
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