Evaluate the following integral:
5 = (Ax + B)(x + 2) + C(x2 + 1)
Equating constants
5 = 2B + C
Equating coefficients of x
0 = 2A + B
Equating coefficients of x2
0 = A + C
Solving, we get
A = – 1,B = 2,C = 1
Thus
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