Evaluate the following integrals:
Sin5x = sin4x.sinx
Assume cos x = t
d(cosx) = dt
- sinx.dx = dt
⇒ 
Substitute t and dt we get
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ - 
⇒ 
But t = cos x
⇒ 
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