Evaluate the following integrals:
∫ x cos3 x2 sin x2 dx
Let cosx2 = t
Then d(cosx2) = dt
Since d(xⁿ) = nxⁿ⁻1 and d(cos x) = -sinx dx
dt = 2x (-sin x2) = -2x sin x2 dx
x sin x2dx = ![]()
hence ∫ x cos3 x2 sin x2 dx = ![]()
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