Evaluate the following integrals:

Assume xex = t
d(xex) = dt
(ex + xex) dx = dt
ex(1 + x) dx = dt
Substituting t and dt
⇒ ![]()
⇒ ![]()
⇒ - cot t + c
But t = xex + 1
⇒ - cot (xex) + c.
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