Evaluate the following integrals:

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Expressing the integral ![]()
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Let
and split,
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Consider ![]()
Let ![]()
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We know that ![]()
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Now consider ![]()
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By partial fraction decomposition,
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⇒ 1 = A (x – 2) + B (x – 3)
⇒ 1 = Ax – 2A + Bx – 3B
⇒ 1 = (A + B) x – (2A + 3B)
⇒ A + B = 0 and 2A + 3B = -1
Solving the two equations,
⇒ 2A + 2B = 0
2A + 3B = -1
-B = 1
∴ B = -1 and A = 1
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Consider ![]()
Let u = x – 3 → dx = du
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We know that ![]()
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Let u = x – 2 → dx = du
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We know that ![]()
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Then,
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Then,
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Then,
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We know that ![]()

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