Evaluate the following integrals:

Let ![]()
We have ![]()
We know cos2θ = 1 – 2sin2θ = 2cos2θ – 1
Hence, in the numerator, we can write ![]()
In the denominator, we can write ![]()
Therefore, we can write the integral as


![]()
[∵ sec2θ – tan2θ = 1]
![]()
Recall
and ![]()

![]()
Thus, ![]()
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