Evaluate the following integrals:

First of all, take ex common from the denominator, so we get
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Assume e - x + 1 =t
d(e - x + 1) = dt
⇒ - e - xdx= dt
⇒ e - xdx= - dt
Substituting t and dt we get
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⇒ ![]()
But t =(e - x + 1)
⇒
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