Evaluate the following integral:
3x + 5 = A(x – 1)(x + 1) + B(x + 1) + C(x – 1)2
Put x = 1
8 = 2B
B = 4
Put x = – 1
– 3 + 5 = 4C
2 = 4C
Put x = 0
5 = – A + B + C
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