Q39 of 865 Page 20

Evaluate the following integrals:

∫ 2x sec3 (x2 + 3) tan (x2 + 3) dx

sec3 (x2 + 3) can be written as sec2 (x2 + 3). sec (x2 + 3)


Now the question becomes


⇒


Assume sec (x2 + 3) = t


d(sec (x2 + 3)) = dt


2x sec (x2 + 3) tan (x2 + 3)dx = dt


Substituting t and dt in the given equation


⇒


⇒


⇒ .


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