Evaluate the following integrals:
∫ cot3x cosec2x dx
Assume cotx = t
⇒ d(cotx) = dt
⇒ - cosec2x.dx = dt
⇒ ![]()
∴ Substituting t and dt in the given equation we get
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
But t = cotx
⇒
.
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