Evaluate the following integrals:
∫ cotx log sin x dx
Assume log(sinx) = t
d(log(sinx)) = dt
⇒ ![]()
⇒ cot x dx = dt
Substituting the values oft and dt we get
⇒ ![]()
⇒ ![]()
But t = log(sinx)
⇒
.
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