Evaluate the following integrals:
∫ sin3 x cos6 x dx
Since power of sin is odd, put cos x = t
Then dt = -sin xdx
Substitute these in above equation,
∫ sin3 x cos6 x dx = ![]()
= ![]()
= ![]()
= ![]()
=
( since ∫xⁿ dx =
+ c
)
= ![]()
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