Evaluate 
Given,
Consider, a=b=1
=
=
=
Now, cosx=A (cosx+sinx) +B 
(cosx+sinx)
=A (cosx+sinx) +B (-sinx+cosx)
Equating ’cosx’ coeff:- Equating ‘sinx’ coeff:-
1=A+B 0=A-B
A=B
1=A+A
2A=1
A=1/2 B=1/2
[since,
(x)+
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