Construct the following quadrilaterals.

(i) Quadrilateral MORE

MO = 6 cm

OR = 4.5 cm

∠M = 60°

∠O = 105°

∠R = 105°

(ii) Quadrilateral PLAN

PL = 4 cm

LA = 6.5 cm

∠P = 90°

∠A = 110°

∠N = 85°

(iii) Parallelogram HEAR

HE = 5 cm

EA = 6 cm

∠R = 85°

(iv) Rectangle OKAY

OK = 7 cm

KA = 5 cm

(i) Step 1: First, we draw the line segment of MO = 6 cm. At point O we draw an angle of 105

Step 2: From point O, we draw an arc measuring 4.5 cm such that it intersects at the line OC.

Step 3: At point R we draw another angle of 105

Step 4: At point M, we draw another angle of 60 and extend M such that it intersects Bb at point E.

(ii) We know that the sum of the quadrilateral is 360°

So, ∠A + ∠P+∠L+∠N = 360°

110°+90°+∠L+85° = 360°

∠L = 75°

Step 1: We will draw the base for the diagram.

Step 2: At both points P and L, we will draw angle 90° and 75° respectively.

Step 3: Taking L as the center we draw an arc of 4.5 cm such that it is intersecting at point A.

Step 4: At point A, we draw another angle of 110 extending such that they intersect at point N.

(iii) Since parallelogram opposite sides are of equal length.

So, HE=AR = 5 cm

EA=HR = 6 cm

Step 1: We will draw the base of measurement AR = 5 cm.

Step 2: At point R we draw an angle of 85.

Step 3: Taking R as a center, we draw an arc of 6 cm intersecting at point E.

Step 4: From point A and from point E, we draw arcs measuring 6 cm and 5 cm respectively such that they are intersecting at point H.

Step 5: Join HA and HE.

(iv) We know that sides of the rectangle are perpendicular to each other.

A rough diagram can be drawn.

Step 1: Taking KO as a base we draw it of 7 cm.

Step 2: We draw an angle of 90 perpendicular at point K.

Step 3: Taking K as center we draw an arc of measuring 5 cm intersecting at point A.

Step 4: From point O and A, we draw arcs of measuring 5 cm and 7 cm, respectively such that they intersect at point Y.

Join YA and YO.